(1/3)x^2+14=26

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Solution for (1/3)x^2+14=26 equation: 



(1/3)x^2+14=26

We move all terms to the left:

(1/3)x^2+14-(26)=0



Domain of the equation: 3)x^2!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+1/3)x^2+14-26=0

We add all the numbers together, and all the variables

(+1/3)x^2-12=0

We multiply all the terms by the denominator


(+1-12*3)x^2=0

We add all the numbers together, and all the variables

(-35)x^2=0

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